x=((x+4)/7)^2

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Solution for x=((x+4)/7)^2 equation: 



x=((x+4)/7)^2

We move all terms to the left:

x-(((x+4)/7)^2)=0

We multiply all the terms by the denominator


x*7)^2)-(((x+4)=0

Wy multiply elements

7x^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{14}=0$

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